## In This post you will get answer of Q.

A ball is thrown up at an angle with the horizontal. Then the total change of momentum by the instant it returns to ground is

Solution:

## Change in momentum of the ball

= mvsin $ theta $ – ( – m v sin $ theta $ ) = 2mvsin $ theta $

= mg $ times frac{ 2 v sin theta }{ g } $

= weight of the ball $ times $ total time of flight