## In This post you will get answer of Q.

A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg. The velocity of 8 kg mass is $6 ms^{-1}$. The kinetic energy of the other mass is

Solution:

## As the initial momentum of the bomb was zero, therefore after explosion the two parts should possess numerically equal momentum i,e $m_A v_A=m_B V_B$

$Rightarrow 4v_A= 8times 6$

$Rightarrow v_A=12ms^{-1}$

Kinetic energy of the other mass

$A=frac{1}{2}m_A v^2_A=frac{1}{2}times 4times (12)^2$

=288 J