> Q. A bomber flying upward at an angle of 53$^circ$ with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g = 10 m s$^{-2}$,the velocity at the time of release of the bomb in $ms^{-1}$ is – LIVE ANSWER TODAY

Q. A bomber flying upward at an angle of 53$^circ$ with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g = 10 m s$^{-2}$,the velocity at the time of release of the bomb in $ms^{-1}$ is

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A bomber flying upward at an angle of 53$^circ$ with the vertical releases a bomb at an altitude of 800 m. The bomb strikes the ground 20 s after its release. If g = 10 m s$^{-2}$,the velocity at the time of release of the bomb in $ms^{-1}$ is

Solution:

-h – ut – $frac{1}{2}$ g t$^2$

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