In This post you will get answer of Q.
A bus is moving on a straight road towards north with a uniform speed of 50 km/hour then it turns left through 90$^{circ}$. If the speed remains unchanged after turning, the increase in the velocity of bus in the turning process is
Solution:
$ v_1 $ 50 km/hr due north
$ v_2$ 50 km/hr due west
– $ v_1$ 50 km/hr due south
Magnitude of change in velocity
= $ | overrightarrow{v_2} – overrightarrow{v_1} | = | overrightarrow{v_2} + ( – overrightarrow{v_1}) | $
= $ sqrt{ v_2^2 + ( – v_1)^2 }$
= $ sqrt{ ( 50)^2 + (50)^2 } $
= 70.7 km/hr along south-west direction
Solution:
$ v_1 $ 50 km/hr due north
$ v_2$ 50 km/hr due west
– $ v_1$ 50 km/hr due south
Magnitude of change in velocity
= $ | overrightarrow{v_2} – overrightarrow{v_1} | = | overrightarrow{v_2} + ( – overrightarrow{v_1}) | $
= $ sqrt{ v_2^2 + ( – v_1)^2 }$
= $ sqrt{ ( 50)^2 + (50)^2 } $
= 70.7 km/hr along south-west direction