## In This post you will get answer of Q.

A capacitor has a resistance of $1200,MOmega$ and capacitance of $22 ,mu F$ . When connected to an a.c. supply of frequency 80 hertz, then the alternating voltage supply required to drive a current of 10 virtual ampere is

Solution:

## $f = 80Hz, I_v=10A$

Current through R, $I_R=frac{E_v}{R}=frac{E_v}{12 times 10^8}$

Current through C $I_c=frac{E_v}{X_c}=2pi,fC,times E_v$

=$2pi times 80 times 22 times 10^{-6}times E_v$

$=352 pi times 10^{-5}times E_v ,I^2_v=I^{2_R} +I^{2_c}$

$(10^2)frac{E_{v^2}}{(12times 10^8)^2}+352times 10^{-5}times E_v)^2$

$=E^2_vleft(frac{1}{144 times 10^{16}}+1.2times 10^{-4}right)$

$E^2_v=frac{100times 10^4}{1.2}E_v=904 ,volt$