## In This post you will get answer of Q.

A circular loop of radius 0.3 cm lies parallel to a much bigger

circular loop of radius 20 cm. The centre of the smaller loop

is on the axis of the bigger loop. The distance between their

centres is 15 cm. If a current of 2.0 A flows through the

bigger loop, then the flux linked with smaller loop is

Solution:

## Magnetic field at the centre of smaller loop

$ , , , , , , , , , , , , B =frac{mu _0 iR_2^2}{2(R_2^2+x^2)^{3/2}}$

Area of smaller loop S = $pi R_1^2$

$therefore , , $Flux through smaller loop $phi$ = BS

Substituting the values we get, $phi = 9.1 times 10^{-11}Wb$