## In This post you will get answer of Q.

A cylindrical vessel containing a liquid is rotated about its axis so that the liquid rises at its sides as shown in the figure. The radius of vessel is $5 ,cm$ and the angular speed of rotation is $omega, rad ,s^{-1}$. The difference in the height, $h ($ in $cm$ ) of liquid at the centre of vessel and at the side will be:

Solution:

Applying pressure equation from A to B

$P_{0}+rho cdot frac{R omega^{2}}{2} cdot R-rho g h=P_{0}$

$frac{rho R^{2} omega^{2}}{2}=rho g h$

$h =frac{ R ^{2} omega^{2}}{2 g }=(5)^{2} frac{omega^{2}}{2 g }=frac{25}{2} frac{omega^{2}}{ g }$