> Q. A force $ F = 2.0, N $ acts on a particle $ P $ in the $ xz $ -plane. The force $ F $ is parallel to $ x $ -axis. The particle $ P $ (as shown in the figure) is at a distance $ 3 ,m $ and the line joining $ P $ with the origin makes angle $ 30^circ $ with the $ x $ -axis. The magnitude of torque on $ P $ with respect to origin $ O $ (in $ N-m $ ) is – LIVE ANSWER TODAY

Q. A force $ F = 2.0, N $ acts on a particle $ P $ in the $ xz $ -plane. The force $ F $ is parallel to $ x $ -axis. The particle $ P $ (as shown in the figure) is at a distance $ 3 ,m $ and the line joining $ P $ with the origin makes angle $ 30^circ $ with the $ x $ -axis. The magnitude of torque on $ P $ with respect to origin $ O $ (in $ N-m $ ) is

In This post you will get answer of Q.
A force $ F = 2.0, N $ acts on a particle $ P $ in the $ xz $ -plane. The force $ F $ is parallel to $ x $ -axis. The particle $ P $ (as shown in the figure) is at a distance $ 3 ,m $ and the line joining $ P $ with the origin makes angle $ 30^circ $ with the $ x $ -axis. The magnitude of torque on $ P $ with respect to origin $ O $ (in $ N-m $ ) is

Solution:

Torque $tau = F cdot r ,sin ,theta$

$= 2 times 3 times sin ,30^{circ}$

$ = 6 times frac{1}{2}$

$tau = 3,N-m$

Leave a Comment