## In This post you will get answer of Q.

A galvanometer of $ 50,Omega $ resistance has 25 divisions. A current of $ 4times {{10}^{-4}} $ A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 V, it should be connected with a resistance of

Solution:

## To convert a galvanometer into .voltmeter, high resistance should be connected in series with it. Let R is the resistance connected in series with the galvanometer. Galvanometer current

$ {{i}_{g}}=frac{V}{G+R} $

Or $ R=frac{V}{{{i}_{g}}}-G $

Given, $ G=50,Omega , $

$ {{i}_{g}}=25times 4times {{10}^{-4}}={{10}^{-2}}A,V=25V $

$ therefore $ $ R=frac{25}{{{10}^{-2}}}-50=2500-50=2450text{ }Omega $