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Q.
A lift is ascending with an acceleration equal to g/3 What will be the time period of a simple pendulum suspended from its ceiling if its time period in stationary lift isT: – LIVE ANSWER TODAYSkip to content

Q.
A lift is ascending with an acceleration equal to g/3 What will be the time period of a simple pendulum suspended from its ceiling if its time period in stationary lift isT:

In This post you will get answer of Q.
A lift is ascending with an acceleration equal to g/3 What will be the time period of a simple pendulum suspended from its ceiling if its time period in stationary lift isT:

Solution:

Here: Acceleration of lift $ (a)=gtext{/}3 $ Initial time period $ {{T}_{1}}=T $ The effective acceleration when it is ascending $ {{g}_{2}}=g-a=g-frac{8}{3}=frac{2g}{3} $ Time period of simple pendulum $ T=2pi sqrt{frac{l}{g}} $ or $ Tpropto frac{sqrt{1}}{g} $ Hence $ frac{{{T}_{1}}}{{{T}_{2}}}=sqrt{frac{{{g}_{2}}}{{{g}_{1}}}}=sqrt{frac{frac{2}{3}g}{g}} $ or $ {{T}_{2}}=left( sqrt{frac{3}{2}} right){{T}_{1}}=left( sqrt{frac{3}{2}} right)T $