> Q. A light rope is wound around a hollow cylinder of mass $4, kg$ and radius $40, cm.$ If the rope is pulled with a force of $40, N.$ it’s angular acceleration is – LIVE ANSWER TODAY

Q. A light rope is wound around a hollow cylinder of mass $4, kg$ and radius $40, cm.$ If the rope is pulled with a force of $40, N.$ it’s angular acceleration is

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A light rope is wound around a hollow cylinder of mass $4, kg$ and radius $40, cm.$ If the rope is pulled with a force of $40, N.$ it’s angular acceleration is

Solution:

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Torque, $tau=I alpha$

$F times r =M r^{2} alpha$

$40 times 0.4=4 times(0.4)^{2} alpha$

$16=0.64 alpha$

$alpha=frac{16}{0.64}$

$=frac{16}{64} times 100$

$=25, rad / s ^{2}$

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