> Q. A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is $ {{T}_{0}} $ in a uniform magnetic field B. Then, the time period of each part in the same magnetic field is – LIVE ANSWER TODAY

Q. A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is $ {{T}_{0}} $ in a uniform magnetic field B. Then, the time period of each part in the same magnetic field is

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A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is $ {{T}_{0}} $ in a uniform magnetic field B. Then, the time period of each part in the same magnetic field is

Solution:

In the case of vertical cutting $ {{T}_{1}}=frac{text{Original time period}}{n} $ $ {{T}_{1}}=frac{{{T}_{0}}}{3} $

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