In This post you will get answer of Q.
A mass of $2.0, kg$ is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion.
The spring constant is $200, N/m$. What should be the minimum amplitude of the motion, so that the mass gets detached from the pan? (Take $ g=10,m/{{s}^{2}} )$
Solution:
Since $F = k cdot a$
A.T. Q :- $F = ma$
$therefore ka=mg$
$Rightarrow a=frac{mg}{k}=frac{2 times 10}{200}$
$=10, cm$
Solution:
Since $F = k cdot a$
A.T. Q :- $F = ma$
$therefore ka=mg$
$Rightarrow a=frac{mg}{k}=frac{2 times 10}{200}$
$=10, cm$