> Q. A monoatomic gas supplied the heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be: – LIVE ANSWER TODAY

Q. A monoatomic gas supplied the heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be:

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A monoatomic gas supplied the heat $Q$ very slowly keeping the pressure constant. The work done by the gas will be:

Solution:

For monoatomic gas at constant pressure

$ frac{Delta U}{Q}=frac{1}{3} $

or $ Delta U=frac{Q}{3} $

Now applying first law of thermodynamics

$ W=Delta Q-Delta U $

$ =Q-,frac{Q}{3},=frac{2Q}{3} $

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