In This post you will get answer of Q.
A paramagnetic substance of susceptibility $ 3times {{10}^{-4}} $ is placed in a magnetic field of $ 4times {{10}^{-4}}A{{m}^{-1}} $ . Then the intensity of .magnetization in the units of $ A{{m}^{-1}} $ is
Solution:
Susceptibility $ (chi ) $ $ =frac{intensitytext{ }oftext{ }magnetisation(I)}{magnetictext{ }field(B)} $
or $ I=chi B $
$ therefore $ $ I=3times {{10}^{-4}}times 4times {{10}^{-4}} $
or $ I=12times {{10}^{-8}}A{{m}^{-1}} $
Solution:
Susceptibility $ (chi ) $ $ =frac{intensitytext{ }oftext{ }magnetisation(I)}{magnetictext{ }field(B)} $
or $ I=chi B $
$ therefore $ $ I=3times {{10}^{-4}}times 4times {{10}^{-4}} $
or $ I=12times {{10}^{-8}}A{{m}^{-1}} $