## In This post you will get answer of Q.

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $s_1$ in the first 10 seconds and distance $s_2$ in the next 10 seconds, then

Solution:

## Let a be the constant acceleration of the particle.

Then $s = ut + frac{1}{2} at^2$

or $s_1 = 0 + frac{1}{2} times a times (10)^2 = 50 a$

and $s_2 = left[ 0 + frac{1}{2} a (20)^2right] – 50a = 150 a $

$therefore , s_2 = 3s_1$