## In This post you will get answer of Q.

A particle moves along x-axis as

$ x=4,(t-2)+a{{(t-2)}^{2}} $

Which of the flowing is true?

Solution:

## Rate of change of displacement is velocity

$ left(v=frac{dx}{dt}right) $

Given, $ x = 4 (t – 2) + a(t – 2)^2 $

using $ frac{d}{dx}x^n=nx^{n-1} $ we have

$ v=frac{dx}{dt}=4+2a(t-2) $

At t = 0, v=4

Acceleration $ a = frac{d^2x}{dt^2} $

$ a=frac{d^2x}{dt^2}=2a $