> Q. A particle moves along x-axis as $ x=4,(t-2)+a{{(t-2)}^{2}} $ Which of the flowing is true? – LIVE ANSWER TODAY

Q. A particle moves along x-axis as $ x=4,(t-2)+a{{(t-2)}^{2}} $ Which of the flowing is true?

In This post you will get answer of Q.
A particle moves along x-axis as
$ x=4,(t-2)+a{{(t-2)}^{2}} $
Which of the flowing is true?

Solution:

Rate of change of displacement is velocity

$ left(v=frac{dx}{dt}right) $

Given, $ x = 4 (t – 2) + a(t – 2)^2 $

using $ frac{d}{dx}x^n=nx^{n-1} $ we have

$ v=frac{dx}{dt}=4+2a(t-2) $

At t = 0, v=4

Acceleration $ a = frac{d^2x}{dt^2} $

$ a=frac{d^2x}{dt^2}=2a $

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