In This post you will get answer of Q.
A person swims in a river aiming to reach exactly on the opposite point on the bank of a river. His speed of swimming is $0.5, m/s$ at an angle of $120^º$ with the direction of flow of water. The speed of water is
Solution:
Let the speed of water $=overrightarrow{u}$
Speed of swimmer $=overrightarrow{v}=0.5,m/sec$
Angle between $=overrightarrow{v}$ and $=overrightarrow{u}$ is $120^°$. Then
$sin,theta=frac{vec{u}}{vec{v}} Rightarrow frac{u}{0.5}=frac{1}{2} or u=0.25,ms^{-1}$
Solution:
Let the speed of water $=overrightarrow{u}$
Speed of swimmer $=overrightarrow{v}=0.5,m/sec$
Angle between $=overrightarrow{v}$ and $=overrightarrow{u}$ is $120^°$. Then
$sin,theta=frac{vec{u}}{vec{v}} Rightarrow frac{u}{0.5}=frac{1}{2} or u=0.25,ms^{-1}$