In This post you will get answer of Q.
A rectangular block is heated from $0^{circ}C$ to $100^{circ}C$. The percentage increase in its length is $0.2%$. The percentage increase in its volume is
Solution:
Volume $V= L^3$
$therefore frac{Delta V}{V} times 100=3 frac{Delta L}{L} times100$
$=3 times 0.2%=0.6% quad $$left(because frac{Delta L}{L}=0.2right)$
Solution:
Volume $V= L^3$
$therefore frac{Delta V}{V} times 100=3 frac{Delta L}{L} times100$
$=3 times 0.2%=0.6% quad $$left(because frac{Delta L}{L}=0.2right)$