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Q. A rod of length L and mass m is kept vertically on the ground. Its potential energy is

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A rod of length L and mass m is kept vertically on the ground. Its potential energy is

Solution:

The potential energy of the rod will be according to the position of the centre of mass of the rod, which is $ frac{L}{2} $ unit above the ground. So, potential energy of the rod $ =mgfrac{L}{2} $

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