In This post you will get answer of Q.
A silver wire of radius $ 0.1text{ }cm $ carries a current of $ 2A $ . If the charge density in silver is $ 5.86times {{10}^{28}}{{m}^{-3}}, $ the drift velocity is
Solution:
$ {{v}_{d}}=frac{I}{pi Ae} $
Given, $ I=2A,,,n=5.86times {{10}^{28}}{{m}^{-3}}, $
$ A=pi {{r}^{2}}=pi {{(0.1times {{10}^{-2}})}^{2}},e=1.6times {{10}^{-19}}C $
$ therefore $ $ {{v}_{d}}=0.68times {{10}^{-4}}m/s $
Solution:
$ {{v}_{d}}=frac{I}{pi Ae} $
Given, $ I=2A,,,n=5.86times {{10}^{28}}{{m}^{-3}}, $
$ A=pi {{r}^{2}}=pi {{(0.1times {{10}^{-2}})}^{2}},e=1.6times {{10}^{-19}}C $
$ therefore $ $ {{v}_{d}}=0.68times {{10}^{-4}}m/s $