In This post you will get answer of Q.
A stone of mass 0.3 kg attached to a 1.5 m long string is whirled around in a horizontal circle at a speed of 6 ms-1. The tension in the string is
Solution:
Here, mass of the stone m = 0.3 kg
Length of a string = 1.5 m
Speed v = 6 m/s
$T=frac{mv^{2}}{R}=frac{left(0.3right)left(6right)^{2}}{1.5}$ =7.2 N
Solution:
Here, mass of the stone m = 0.3 kg
Length of a string = 1.5 m
Speed v = 6 m/s
$T=frac{mv^{2}}{R}=frac{left(0.3right)left(6right)^{2}}{1.5}$ =7.2 N