In This post you will get answer of Q.
A straight wire of mass $300 ,g$ and length $ 2.5text{ }m $ carries a current of $ 3.5text{ }A $ . It is suspended in mid-air by a uniform horizontal magnetic field $B$. What is the magnitude of the magnetic field?
Solution:
Here weight of the wire is balanced by the extene magnetic force.
So, $ Bil=mg $
$ B=frac{mg}{il} $
$ =frac{300times {{10}^{-3}}times 10}{35times 2.5}=0.34,T $
Solution:
Here weight of the wire is balanced by the extene magnetic force.
So, $ Bil=mg $
$ B=frac{mg}{il} $
$ =frac{300times {{10}^{-3}}times 10}{35times 2.5}=0.34,T $