## In This post you will get answer of Q.

A torque of $1, N-m$ is applied to a wheel which is at rest. After $2$ seconds the angular momentum in $kg,-m^2/s$ is

Solution:

## As; $tau=I alpha$

So, $alpha=frac{tau}{I}$

Now $W=alpha Delta t$

And $ L =I W $

$ =I alpha Delta t $

$ =I frac{tau}{I} Delta t=tau Delta t $

$ =1(N .m) times 2(s) $

$=2 ,kgm ^{2} s ^{-1} $