In This post you will get answer of Q.
A torque of $1, N-m$ is applied to a wheel which is at rest. After $2$ seconds the angular momentum in $kg,-m^2/s$ is
Solution:
As; $tau=I alpha$
So, $alpha=frac{tau}{I}$
Now $W=alpha Delta t$
And $ L =I W $
$ =I alpha Delta t $
$ =I frac{tau}{I} Delta t=tau Delta t $
$ =1(N .m) times 2(s) $
$=2 ,kgm ^{2} s ^{-1} $
Solution:
As; $tau=I alpha$
So, $alpha=frac{tau}{I}$
Now $W=alpha Delta t$
And $ L =I W $
$ =I alpha Delta t $
$ =I frac{tau}{I} Delta t=tau Delta t $
$ =1(N .m) times 2(s) $
$=2 ,kgm ^{2} s ^{-1} $