In This post you will get answer of Q.
A truck accelerates from speed $upsilon ,to, 2upsilon$. Work done in during this is
Solution:
Work done to accelerate from $0$ to $v$ is, $W_{1}=frac{1}{2} ,m v^{2}$
Work done to accelerate from $v$ to $2 ,v$ is
$W_{2} =frac{1}{2} ,m,(2 v)^{2} $
$Rightarrow Delta W =W_{2}-W_{1}=frac{1}{2} ,m(2 v)^{2}-frac{1}{2} ,m v^{2} $
$=4, W_{1}-W_{1}=3 ,W_{1}$
Solution:
Work done to accelerate from $0$ to $v$ is, $W_{1}=frac{1}{2} ,m v^{2}$
Work done to accelerate from $v$ to $2 ,v$ is
$W_{2} =frac{1}{2} ,m,(2 v)^{2} $
$Rightarrow Delta W =W_{2}-W_{1}=frac{1}{2} ,m(2 v)^{2}-frac{1}{2} ,m v^{2} $
$=4, W_{1}-W_{1}=3 ,W_{1}$