## In This post you will get answer of Q.

A truck accelerates from speed $upsilon ,to, 2upsilon$. Work done in during this is

Solution:

## Work done to accelerate from $0$ to $v$ is, $W_{1}=frac{1}{2} ,m v^{2}$

Work done to accelerate from $v$ to $2 ,v$ is

$W_{2} =frac{1}{2} ,m,(2 v)^{2} $

$Rightarrow Delta W =W_{2}-W_{1}=frac{1}{2} ,m(2 v)^{2}-frac{1}{2} ,m v^{2} $

$=4, W_{1}-W_{1}=3 ,W_{1}$