> Q. A uniform rod of length of $1, m$ and mass of $2, kg$ is attached to a side support at $O$ as shown in the figure. The rod is at equilibrium due to upward force $T$ acting at $P$. Assume the acceleration due to gravity as $10 , m/s^2$. The value of $T$ is – LIVE ANSWER TODAY

Q. A uniform rod of length of $1, m$ and mass of $2, kg$ is attached to a side support at $O$ as shown in the figure. The rod is at equilibrium due to upward force $T$ acting at $P$. Assume the acceleration due to gravity as $10 , m/s^2$. The value of $T$ is

In This post you will get answer of Q.
A uniform rod of length of $1, m$ and mass of $2, kg$ is attached to a side support at $O$ as shown in the figure. The rod is at equilibrium due to upward force $T$ acting at $P$. Assume the acceleration due to gravity as $10 , m/s^2$. The value of $T$ is

Solution:

The one end of the uniform rod is fixed and force $T$ is acting in upward direction

So, at point $P$,

$T =frac{m g}{2} $

$=frac{2 times 10}{2} $

$=10 ,N$

Leave a Comment