> Q. A vernier calipers has $1, mm$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier calipeis, the least count is – LIVE ANSWER TODAY

Q. A vernier calipers has $1, mm$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier calipeis, the least count is

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A vernier calipers has $1, mm$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier calipeis, the least count is

Solution:

Least count of vernier calipers

LC = 1MSD – 1 VSD

$ = frac { text{Smallest division on main scale}}{text{Number of divisions on vernier scale }} $

20 divisions of vernier scale = 16 divisions of main scale

$therefore 1 , VSD= frac {16}{20}mm=0.8 , mm $

$therefore LC=1MSD-1 VSD=1 , mm-0.8 , mm=0.2 , mm $

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