## In This post you will get answer of Q.

A wire of length $ 100, cm $ is connected to a cell of emf $ 2, V $ and negligible internal resistance. The resistance of the wire is $ 3 Omega $ the additional resistance required to produce a potential difference of $ 1 ,m V/cm $ on the wire is

Solution:

## Current, $ i = frac{E}{(R + V)}$

$= frac{2}{3+R} = frac{2}{(3+R)}$

$ V = frac{2}{(3+R)} times 3$

$frac{v’}{l} = frac{V}{L}$

$ 1 times 10^{-3} = frac{2times 3}{(3 + R)} times 3$

$ frac{1}{10} = frac{2times 3}{(3 + R ) times 100}$

$ 3 + R = 60$

$ R = 60.3$

$ R = 57,Omega$