## In This post you will get answer of Q.

A wire of resistance $3Omega$ is cut into three equal pieces, which are joined to form a triangle. The equivalent resistance between any two corners of the triangle is :

Solution:

## It will be a case of one resistance of 1 $Omega$ connected in parallel with two resistance in serice each of 1 $Omega$ . Hence $frac{1}{R_p} =frac{1}{1} + frac{1}{2} = frac{3}{2} $.

$i.e. , R_p = frac{2}{3}$