In This post you will get answer of Q.
According to Einsteins photoelectric equation the graph between the kinetic energy of photoelectrons ejected and the frequency of incident radiation is
Solution:
Compare the Einsteins photo- electric equation with the equation of straight line.
Einsteins photoelectric equation is
$ KE=hv-phi $ …(i)
where $ phi = $ work function of metal
Comparing above Eq. (i) with equation of a straight line
$ y=mx+c $ we get $ m=h,c=-phi $
Therefore, if we draw a graph between kinetic energy and frequency, then a straight line cutting the frequency axis at
$ {{v}_{0}} $ and giving an intercept of (-(|)) on the kinetic energy axis, is obtained.

Solution:
Compare the Einsteins photo- electric equation with the equation of straight line.
Einsteins photoelectric equation is
$ KE=hv-phi $ …(i)
where $ phi = $ work function of metal
Comparing above Eq. (i) with equation of a straight line
$ y=mx+c $ we get $ m=h,c=-phi $
Therefore, if we draw a graph between kinetic energy and frequency, then a straight line cutting the frequency axis at
$ {{v}_{0}} $ and giving an intercept of (-(|)) on the kinetic energy axis, is obtained.