## In This post you will get answer of Q.

An inductive circuit contains a resistance of $10, Omega$ and an inductance of $2.0, H$. If an $AC$ voltage of $120, V$ and frequency of $60, Hz$ is applied to this circuit, the current in the circuit would be nearly

Solution:

## Here, impedence $z=sqrt{R^{2}+X^{2}_{L}}$

$=sqrt{left(10right)^{2}+left(2pitimes60times2right)^{2}}=753.7$

$therefore$ Current $i=frac{V}{Z}=frac{120}{753.7}=0.159,A$