## In This post you will get answer of Q.

An LCR circuit contains resistance of $110 Omega$

and a supply of $220 V$ at $300 rad / s$ angular

frequency. If only capacitance is removed from

the circuit, current lags behind the voltage by

$45^{circ} .$ If on the other hand, only inductor is

removed the current leads by $45^{circ}$ with the

applied voltage. The $rms$ current flowing in the circuit will be :

Solution:

## $tan 45^{circ}=frac{1}{omega C R}=frac{omega L}{R} $

$Rightarrow X_{L}=X_{C}$

$Rightarrow$ resonance

$i =frac{ V }{ R }$

$=frac{220}{110}=2 A$