Q. Consider the junction diode as ideal. The value of current flowing through $AB$ is :

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Consider the junction diode as ideal. The value of current flowing through $AB$ is :

Solution:

Since diode is in forward bias $ i = frac{Delta V}{R} = frac{4 – (-6)}{1 times 10^{3}} = frac{10}{10^3} = 10^{-2} A $