In This post you will get answer of Q.
Current in a coil changes from $4 ,A$ to zero in $0.1$ second and the emf induced is $100, V$. The self inductance of the coil is
Solution:
Induced emf , $e =frac{-L d I}{d t} $
$therefore 100 =frac{-L[0-4]}{0.1} $
$Rightarrow L =frac{100 times 0.1}{4} $
$=2.5 ,H$
Solution:
Induced emf , $e =frac{-L d I}{d t} $
$therefore 100 =frac{-L[0-4]}{0.1} $
$Rightarrow L =frac{100 times 0.1}{4} $
$=2.5 ,H$