In This post you will get answer of Q.
Equation of a progressive wave is given by $y= sinbegin {pmatrix}frac{t}{2}-frac{x}{2}end{pmatrix}$, where $t$ is in seconds and $x$ is in metre. Then the distance through which the wave moves in $8$ second is (in metre).
Solution:
Standard equation of a progressive wave is;
$ y = a, sin , 2pi left(frac{t}{T} – frac{x}{lambda} right)$
The given equation $y = a , sin , pi left( frac{t}{2} – frac{x}{4} right) $ can be written as
$y = a , sin , 2 pi left( frac{t}{4} -frac{x}{8} right)$
Comparing eqn. (i) and (ii), T = 4s and $lambda$ = 8m
Distance = Velocity $times $ Time = $frac{lambda}{T} times t = frac{8}{4} times 8 $ = 16 m
Solution:
Standard equation of a progressive wave is;
$ y = a, sin , 2pi left(frac{t}{T} – frac{x}{lambda} right)$
The given equation $y = a , sin , pi left( frac{t}{2} – frac{x}{4} right) $ can be written as
$y = a , sin , 2 pi left( frac{t}{4} -frac{x}{8} right)$
Comparing eqn. (i) and (ii), T = 4s and $lambda$ = 8m
Distance = Velocity $times $ Time = $frac{lambda}{T} times t = frac{8}{4} times 8 $ = 16 m