> Q. figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be: – LIVE ANSWER TODAY

Q. figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:

In This post you will get answer of Q.
figure below shows two paths that may be taken by a gas to go from a state A to a state C.
In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be:

Solution:

In cyclic process ABCA,

$Delta ce{U_{cyclic}} = 0$

$ce{Q_{cyclic} = W_{cyclic}}$

$ce{Q_{AB} = Q_{bc} + Q_{CA} =}$ closed loop area.

$400 + 100+ Q_{CA} = frac{1}{2}times (2times 10^{-3}) times 4times 10^4$

$ce{400 +100 Q_{AC = 40}}$

$ce{Q_{AC} = 460 J}$

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