## In This post you will get answer of Q.

For circuit the equivalent capacitance between P & Q is:

Solution:

## $ frac{1}{{{C}_{eq}}}=frac{1}{3C}+frac{1}{2C}+frac{1}{C}=frac{2+3+6}{6C}=frac{11}{6C} $

$ {{C}_{eq}}=frac{6C}{11} $