In This post you will get answer of Q.
Four capacitors of equal capacitance have an equivalent capacitance $ C_{1}$ when connected in series and an equivalent capacitance $ C_{2}$ when connected in parallel. The ratio $ frac{C_{1}}{C_{2}} $ is:
Solution:
$ C_{1}=frac{C}{4} , and , C_{2} =4C Rightarrow frac{C_{1}}{C_{2}}=frac{1}{16}$
Solution: