> Q. Given that $R_1$= $2Omega$ ,$ R_2 = 3Omega$ and $R_3 = 6 Omega$, combinations which will give an effective resistance of $4Omega$ is – LIVE ANSWER TODAY

Q. Given that $R_1$= $2Omega$ ,$ R_2 = 3Omega$ and $R_3 = 6 Omega$, combinations which will give an effective resistance of $4Omega$ is

In This post you will get answer of Q.
Given that $R_1$= $2Omega$ ,$ R_2 = 3Omega$ and $R_3 = 6 Omega$, combinations which will give an effective resistance of $4Omega$ is

Solution:

$frac{R_2}{R_3}$ in parallel give 2 $Omega$. So 2 $times$ 2 = 4 $Omega$

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