## In This post you will get answer of Q.

If the surface tension of water is $ce{0.06, N, m^{-1}}$, then the capillary rise in a tube of a diameter 1 mm is (Take $theta$ = 0°)

Solution:

## As $ h = frac{ 2S ,cos , theta}{r rho g}$

= $frac{ 2 times 0.06 times cos , 0^circ}{0.5 times 10^{-3} times 10^3 times 9.8}$

= $ce{2.44 times 10^{-2} , m = 2.44 , cm}$