## In This post you will get answer of Q.

In a photoelectric effect experiment, the graph of stopping potential $V$ versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased

Solution:

## $eV =frac{ hc }{lambda}-phi$

$V =left(frac{ hc }{ e }right)left(frac{1}{lambda}right)-phi$

Slope of the line in above equation and all other terms are independent of intensity. The graph does not change.