> Q. In a series $LCR$ circuit, the phase difference between the voltage and the current is $45^°$. Then the power factor will be – LIVE ANSWER TODAY

Q. In a series $LCR$ circuit, the phase difference between the voltage and the current is $45^°$. Then the power factor will be

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In a series $LCR$ circuit, the phase difference between the voltage and the current is $45^°$. Then the power factor will be

Solution:

Here, $phi = 45^°$

In series $LCR$ circuit, power factor $= cosphi$

$therefore cos,phi=cos,45^{circ}=frac{1}{sqrt{2}}$

$=0.707$.

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