> Q. In a Zener diode regulated power supply, unregulated DC input of $10, V$ is applied. If the resistance $left(R_{s}right)$ connected in series with a Zener diode is $200, Omega$ and the Zener voltage $V_{z}=5, V$, the current across the resistance $R_{s}$ is – LIVE ANSWER TODAY

Q. In a Zener diode regulated power supply, unregulated DC input of $10, V$ is applied. If the resistance $left(R_{s}right)$ connected in series with a Zener diode is $200, Omega$ and the Zener voltage $V_{z}=5, V$, the current across the resistance $R_{s}$ is

In This post you will get answer of Q.
In a Zener diode regulated power supply, unregulated DC input of $10, V$ is applied. If the resistance $left(R_{s}right)$ connected in series with a Zener diode is $200, Omega$ and the Zener voltage $V_{z}=5, V$, the current across the resistance $R_{s}$ is

Solution:

Voltage drop across $R_{s}$ is

$(10-5)=5, V$

$therefore I= frac{V}{R_{s}}=frac{5}{200}=0.025, A $

$ =2, mA $

Leave a Comment