In This post you will get answer of Q.
In AC circuit a resistance of $ R,Omega , $ is connected in series with an inductance L. If the phase difference between the current and voltage is $ 45{}^circ , $ the inductive reactance will be
Solution:
Phase difference in R-L circuit
$ phi ={{tan }^{-1}}left( frac{{{X}_{L}}}{R} right) $
$ tan 45{}^circ =frac{{{X}_{L}}}{R} $
$ {{X}_{L}}=R $
Solution:
Phase difference in R-L circuit
$ phi ={{tan }^{-1}}left( frac{{{X}_{L}}}{R} right) $
$ tan 45{}^circ =frac{{{X}_{L}}}{R} $
$ {{X}_{L}}=R $