Q. In the circuit shown above, an input of 1V is fed into the inverting input of an ideal Op-amp A. The output signal V$_{out}$ will be

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In the circuit shown above, an input of 1V is fed into the inverting input of an ideal Op-amp A. The output signal V$_{out}$ will be

Solution:

For the Op-amp shown above, we have

$frac{V_{o}}{V_{I}}=frac{R_{f}}{R_{I}}$

Comparing this circuit with the given one, We get $V_{I} =1V, R_{f} =10kOmega=10times10^{3}Omega$

$R_{I} = 1kOmega=1times10^{3}Omega$

$thereforefrac{V_{o}}{1}=-frac{10times10^{3}}{1times10^{3}} Rightarrow V_{o}=-10V$