> Q. Light is incident on a glass surface at polarizing angle of $57.5^{circ}$. Then the angle between the incident ray and the refracted ray is – LIVE ANSWER TODAY

Q. Light is incident on a glass surface at polarizing angle of $57.5^{circ}$. Then the angle between the incident ray and the refracted ray is

In This post you will get answer of Q.
Light is incident on a glass surface at polarizing angle of $57.5^{circ}$. Then the angle between the incident ray and the refracted ray is

Solution:

When a light is incident at polarising angle, the reflected and refracted rays are perpendicular to each other as shown in the figure,

image

where $i_p$ is the angle of incidence and $r$ is the angle of reflection, $r’$ is the angle of refraction.

Given, $i_p = 57.5^{circ}$

Let $theta$ be the angle between the incident ray and the refracted ray.

From figure,

$theta = i_p + r + 90^{circ} $

$= 2i_p + 90^{circ}$

$ = 2 times 57.5^{circ} + 9.^{circ}$

$ = 205^{circ}quad [because i_p = r]$

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