In This post you will get answer of Q.
Light is incident on a glass surface at polarizing angle of $57.5^{circ}$. Then the angle between the incident ray and the refracted ray is
Solution:
When a light is incident at polarising angle, the reflected and refracted rays are perpendicular to each other as shown in the figure,
where $i_p$ is the angle of incidence and $r$ is the angle of reflection, $r’$ is the angle of refraction.
Given, $i_p = 57.5^{circ}$
Let $theta$ be the angle between the incident ray and the refracted ray.
From figure,
$theta = i_p + r + 90^{circ} $
$= 2i_p + 90^{circ}$
$ = 2 times 57.5^{circ} + 9.^{circ}$
$ = 205^{circ}quad [because i_p = r]$
Solution:
When a light is incident at polarising angle, the reflected and refracted rays are perpendicular to each other as shown in the figure,
where $i_p$ is the angle of incidence and $r$ is the angle of reflection, $r’$ is the angle of refraction.
Given, $i_p = 57.5^{circ}$
Let $theta$ be the angle between the incident ray and the refracted ray.
From figure,
$theta = i_p + r + 90^{circ} $
$= 2i_p + 90^{circ}$
$ = 2 times 57.5^{circ} + 9.^{circ}$
$ = 205^{circ}quad [because i_p = r]$