> Q. Silver and a zinc voltameters are connected in series and a current is passed through them for a time t, liberating W g of zinc. The weight of silver deposited is [Given $ECE$ of silver $= 1.12 times 10^{-6}, kg/C$, $ECE$ of zinc $= 3.39 times 10^{-7}, kg/C$] – LIVE ANSWER TODAY

Q. Silver and a zinc voltameters are connected in series and a current is passed through them for a time t, liberating W g of zinc. The weight of silver deposited is [Given $ECE$ of silver $= 1.12 times 10^{-6}, kg/C$, $ECE$ of zinc $= 3.39 times 10^{-7}, kg/C$]

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Silver and a zinc voltameters are connected in series and a current is passed through them for a time t, liberating W g of zinc. The weight of silver deposited is [Given $ECE$ of silver $= 1.12 times 10^{-6}, kg/C$, $ECE$ of zinc $= 3.39 times 10^{-7}, kg/C$]

Solution:

As silver and zinc voltameters are connected in series, therefore same current passes through two voltameters for same time t

According to Faraday’s second law of electrolysis

$frac{m_{Ag}}{m_{zn}}=frac{Z_{Ag}}{Z_{zn}}=frac{left(1.12times10^{-6} kg /Cright)}{left(3.39times10^{-7} kg /Cright)}$

$frac{m_{Ag}}{m_{zn}}=3.3$

or $m_{Ag}=3.3,Wg$

[Given : $m_{zn}=w,g]$

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