## In This post you will get answer of Q.

The angle of incidence for a ray of light at a refracting surface of a prism is $45^{circ}$. The angle of prism is $60^{circ }$. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are :

Solution:

## $i = 45^{circ} ; A = 60^{circ} ; delta_m = 2i – A = 30^{circ}$

$mu = frac{sinleft(frac{A + delta_{m}}{2}right)}{sin A/2} = frac{sin45^{circ}}{sin30^{circ}} = frac{1}{sqrt{2}}. frac{2}{1} = sqrt{2} $