In This post you will get answer of Q.
The collector supply voltage is $6 ,V$ and the voltage drop across a resistor of $ 600,Omega $ . in the collector circuit is $0.6 ,V$, in a transistor connected in common emitter mode. If the current gain is $20$, the base current is
Solution:
$ {{i}_{C}}{{R}_{C}}={{V}_{C}} $
$ {{i}_{C}}=frac{{{V}_{C}}}{{{R}_{C}}}=frac{0.6}{600}=1,mA $
$ therefore $ $ beta =frac{{{i}_{C}}}{{{i}_{B}}} $
or $ {{i}_{B}}=frac{{{i}_{C}}}{beta }=frac{1}{20}=0.05,mA $
Solution:
$ {{i}_{C}}{{R}_{C}}={{V}_{C}} $
$ {{i}_{C}}=frac{{{V}_{C}}}{{{R}_{C}}}=frac{0.6}{600}=1,mA $
$ therefore $ $ beta =frac{{{i}_{C}}}{{{i}_{B}}} $
or $ {{i}_{B}}=frac{{{i}_{C}}}{beta }=frac{1}{20}=0.05,mA $