In This post you will get answer of Q.
The displacement-time graph of a moving particle is shown below. The instantaneous velocity of the particle is negative at the point
Solution:
The slope of the tangent at any point on the displacement-time graph gives instantaneous velocity at that instant. In the given graph, the slope is negative at point $E$.
The velocity (v)$ =frac{ds}{dt}$.
Therefore, instantaneous velocity at point E is negative.
Solution:
The slope of the tangent at any point on the displacement-time graph gives instantaneous velocity at that instant. In the given graph, the slope is negative at point $E$.
The velocity (v)$ =frac{ds}{dt}$.
Therefore, instantaneous velocity at point E is negative.